为帮助大家能在6月18日的比赛中有一个更好的成绩，我会将蓝桥杯官网上的历届决赛题目的四类语言题解都发出来。希望能对大家的成绩有所帮助。

今年的最大目标就是能为【一亿技术人】创造更高的价值。

资源限制

内存限制：256.0MB   C/C++时间限制：1.0s   Java时间限制：3.0s   Python时间限制：5.0s

C++

#include <bits/stdc++.h>
using namespace std;
#define ll long long
const int maxn = 1005;
int ans = 0 ;
int n;
map<int, int> mp;
void f(int a[],int va[]){
	
	for(int i=1;i<=n;i++){
		int cnt = 1;
		mp.clear();
		for(int j=i+1;j<=n;j++){
			if(va[i] == va[j]){
				if(a[i] == a[j]){
					cnt++;
				}
				ans = max(ans , cnt);
				continue ;
			}
			int dx = a[i] - a[j];
			int dv = va[j] - va[i];
			if(dv != 0){
				int t = dx/dv;
				if( dx%dv != 0 || t < 0)
					continue ;
				mp[t]++;
				ans = max(ans , mp[t] + cnt);
			}else{
				if(dx == 0){
					mp[0]++;
					ans = max(ans , mp[0] + cnt);
				}
				
			}		
		}
		
	}
	
	//cout<<"1"<<endl;
	return ;
}

int x[maxn],y[maxn],vx[maxn],vy[maxn];
int main(){
	cin>>n;
	for(int i=1;i<=n;i++){
		int v;
		char d;
		cin>>x[i]>>y[i]>>v>>d;
		if(d == 'R'){
			vx[i] = v;
		}
		if(d == 'L'){
			vx[i] = -v;
		}
		if(d == 'U'){
			vy[i] = v;
		}
		if(d == 'D'){
			vy[i] = -v;
		}
	}
	f(x,vx);
	f(y,vy);
	cout<<ans<<endl;
	return 0;
}

Java

import java.util.ArrayList;
import java.util.Scanner;

public class Main {
	static int X[], Y[], vx[], vy[];
	static int mx = 0;
	static int n;
	static int m[];

	static void f(int X[], int vx[]) {
		for (int i = 1; i < n; i++) {
			int cnt = 1;
			ArrayList list=new ArrayList();
			for (int j = i + 1; j <= n; j++) {
				if (vx[i] == vx[j]) {
					if (X[i] == X[j])
						cnt++;
					mx = Math.max(cnt, mx);
					continue;
				}
				int dx = X[i] - X[j], dv = vx[j] - vx[i];
				int t = dx / dv;
				if (dx % dv != 0 || t < 0) {
					continue;
				}
				m[t]++;
				if(!list.contains(t)) {
					list.add(t);
				}
				mx = Math.max(mx, m[t] + cnt);
			}
			for(int j=0;j<list.size();j++) {
				m[(int) list.get(j)]=0;
			}
		}
	}

	public static void main(String[] args) {
{
			m = new int[1000000];
			Scanner in = new Scanner(System.in);
			n = in.nextInt();
			X = new int[1001];
			Y = new int[1001];
			vx = new int[1001];
			vy = new int[1001];
			for (int i = 1; i <= n; i++) {
				int v;
				char d;
				X[i] = in.nextInt();
				Y[i] = in.nextInt();
				v = in.nextInt();
				d = in.next().charAt(0);
				if (d == 'R') {
					vx[i] = v;
				}
				if (d == 'L') {
					vx[i] = -v;
				}

				if (d == 'U') {
					vy[i] = v;

				}
				if (d == 'D') {
					vy[i] = -v;
				}
			}
			f(X, vx);
			f(Y, vy);
			System.out.println(mx);
		}
	}
}