蓝桥杯官网 试题 PREV-225 历届真题 成绩分析【第十一届】【决赛】【研究生组】【C++】【C】【Java】【Python】四种解法

为帮助大家能在6月18日的比赛中有一个更好的成绩,我会将蓝桥杯官网上的历届决赛题目的四类语言题解都发出来。希望能对大家的成绩有所帮助。

今年的最大目标就是能为【一亿技术人】创造更高的价值。


资源限制

内存限制:256.0MB C/C++时间限制:1.0s Java时间限制:3.0s Python时间限制:5.0s

C++

#include <bits/stdtr1c++.h>
using namespace std::tr1;
using namespace std;
int main()
{
    int n;
    cin >> n;
    int sum = 0, tp;
    int mx, mi;
    mx = 0, mi = 100;
    for (int i = 0; i < n; i++)
    {
        cin >> tp;
        sum += tp;
        mx = max(mx, tp);
        mi = min(mi, tp);
    }
    unordered_map<int, int> ump;
    printf("%d\n%d\n%.2f\n", mx + ump.size(), mi, 1.0 * sum / n + 1e-8);
    return 0;
}

C

#include<stdio.h>
int main()
{
    int i;
    float p, max = -1, min = 1000;
    float grades,av, sum = 0;
    scanf("%f", &p);
    for(i=0;i<p;i++)
    {
        scanf("%f", &grades);
        if (grades < min)
            min = grades;
        if (grades > max)
            max = grades;
        sum += grades;
    }
    av = sum / p;
    printf("%.0f\n%.0f\n%.2f", max, min,av);
    return 0;
}

Java

import java.io.*;
import java.math.BigDecimal;
public class Main {
	static class Input{
		StreamTokenizer in = new StreamTokenizer(new BufferedReader(new InputStreamReader(System.in)));
		public int nextInt() throws IOException{
			in.nextToken();
			return (int)in.nval;
		}
	}
	
	public static void main(String args[]) throws Exception{
		Input in = new Input();
		int n = in.nextInt();
		int sum = 0;
		int max = 0;
		int min = Integer.MAX_VALUE;
		for(int i=0;i<n;i++) {
			int s = in.nextInt();
			if(s > max) {
				max = s;
			}
			if(s < min) {
				min = s;
			}
			sum +=s;
		}
		BigDecimal r = new BigDecimal(sum+"").divide(new BigDecimal(n+""), 2, BigDecimal.ROUND_HALF_UP);
		System.out.println(max);
		System.out.println(min);
		System.out.println(r);
	}
	
}

Python

n = int(input())
lists = []
sum1 = 0
for i in range(0, n):
    lists.append(int(input()))
for i in range(0, len(lists)):
    sum1 += lists[i]
print(max(lists))
print(min(lists))
print('%0.2f' % (sum1/len(lists)))

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转载自blog.csdn.net/feng8403000/article/details/125032711