题目描述
M×N的矩阵,从左上角走,只能向右或者向下走,要求走过的每个元素的值加起来的和最大,步数不限
代码实现
import numpy as np
def max_way(a,m,n):
dp=[[0]*n for i in range(m)]
dp[0][0]=a[0][0]
for i in range(1,m):
dp[i][0]=dp[i-1][0]+a[i][0]
for j in range(1,n):
dp[0][j]=dp[0][j-1]+a[0][j]
for i in range(1,m):
for j in range(1,n):
dp[i][j]=max(dp[i-1][j]+a[i][j],dp[i][j-1]+a[i][j])
#print(dp)
#求矩阵中元素的最大值
ls=[]
for i in range(m):
ls.append(max(dp[i]))
return max(ls)
a=[[2,5,6,4],[5,8,7,3],[9,5,1,4]]
#不使用numpy
# =============================================================================
# print(len(a))#行数
# print(len(a[0]))#列数
# #使用numpy
# row=np.shape(a)[0]#求矩阵的行数
# col=np.shape(a)[1]#求矩阵的列数
# print(row,col)
# =============================================================================
print(max_way(a,3,4))
输出