从字符串"100+200-50*2/5"中提取出来数字和运算符
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int analysis_data(const char *str, int *value, int *value_count, char *operator, int *operator_count)
{
int value_index = 0;
int operator_index = 0;
int n = 0;
if (str == NULL || value == NULL || value_count == NULL || operator == NULL || operator_count == NULL) {
return -1;
}
while (*str != '\0') {
n = 0;
while (*str >= '0' && *str <= '9') {
n = n * 10 + (*str - '0');
str++;
}
if (*str == '+' || *str == '-' || *str == '*' || *str == '/') {
operator[operator_index++] = *str;
str++;
}
value[value_index++] = n;
}
*value_count = value_index;
*operator_count = operator_index;
return 0;
}
int main()
{
char buffer[1024] = "100+200-50*2/5";
int value[1024];
int value_count = 0;
char operator[1024];
int operator_count = 0;
int result = 0;
memset(value, 0x00, sizeof(value) / sizeof(int));
memset(operator, 0x00, sizeof(operator));
analysis_data(buffer, value, &value_count, operator, &operator_count);
int i = 0;
for (i = 0; i < value_count; i++) {
printf("value: %d\n", value[i]);
}
for (i = 0; i < operator_count; i++) {
printf("operator: %c\n", operator[i]);
}
return 0;
}
运行结果:
value: 100
value: 200
value: 50
value: 2
value: 5
operator: +
operator: -
operator: *
operator: /