【剑指offer】二叉树的深度python实现

剑指offer题目:输入一棵二叉树,求该树的深度。从根结点到叶结点依次经过的结点(含根、叶结点)形成树的一条路径,最长路径的长度为树的深度。

思路:深度使用递归


# -*- coding:utf-8 -*-
# class TreeNode:
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution:
    def TreeDepth(self, pRoot):
        # write code here
        if pRoot == None: 
            return 0
        #递归函数,调用solution
        leftDepth= Solution.TreeDepth(self,pRoot.left);
        rightDepth= Solution.TreeDepth(self,pRoot.right);
        if leftDepth>rightDepth:
            return leftDepth+1
        else: return rightDepth+1 

猜你喜欢

转载自blog.csdn.net/acycy/article/details/80343699