题目
类型:模拟
难度:简单
题意:旋转180度后判断是否产生了一个有效的新数,180度不仅从数字本身,串也要反转。
class Solution {
public:
bool confusingNumber(int N) {
int a[10]={0}, b[10]={0};
int ord = 0, k = 0, nw = 0;
do{
a[k++] = N%10;
N/=10;
}while(N);
for(int i = 0; i < k;i++){
if(a[i] == 0||a[i] == 1||a[i] == 8) ord++, b[i] = a[i];
else if(a[i] == 6) nw++, b[i] = 9;
else if(a[i] == 9) nw++, b[i] = 6;
else b[i] = a[i];
}
if(ord+nw==k){
for(int i = 0; i < k; i++) {
if(a[i]!=b[k-1-i]) return true;
}
}
return false;
}
};