/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* deleteDuplicates(ListNode* head) {
if(head == NULL)
return head;
ListNode* p = head;
int tmp = p->val;
ListNode* pre = p;
p = p->next;
while(p)
{
if(p->val == tmp)
{
pre->next = p->next;
p = pre;
}
pre = p;
tmp = pre->val;
p = p->next;
}
return head;
}
};
就很简单
对哦 还要把删除的结点的内存给释放掉,我就懒得加了