题目描述:
case1:
arr1 = [1,2,3]
arr2 = [1,2,3,4]
输出:[1,2,3]
case2:
arr1 = [1,2,2,3]
arr2 = [1,2,2,3,4]
输出:[1,2,2,3]
题解:
// 数组转json
// [1,2,3,3,3] => {1:1,2:1,3:3}
// 输出描述:key为数组项的值,value为这个值出现的次数
const arr2json = (arr) => arr.reduce((prev, item) => {
if (prev[`${item}`]) {
prev[`${item}`]++
} else {
prev[`${item}`] = 1
}
return prev;
}, {})
const findSame = (arr1, arr2) => {
const json = arr2json(arr2);
return arr1.filter((item)=>{
if(json[`${item}`]>0){
json[`${item}`]--;
return item;
}
})
}
var res =findSame([1,2,3,4,5,5,6],[2,3,4,5,5,6]);
console.log(res);