assume cs:abc
abc segment
mov ax, 2 ;ax=2
add ax, ax ;ax+=ax=4
add ax, ax ;ax+=ax=8
mov ax, 4c00H
int 21H
abc ends
end
思路就是先把2赋值给AX寄存器,再执行两次AX自加
assume cs:abc
abc segment
mov ax, 2 ;ax=2
add ax, ax ;ax+=ax=4
add ax, ax ;ax+=ax=8
mov ax, 4c00H
int 21H
abc ends
end
思路就是先把2赋值给AX寄存器,再执行两次AX自加