二叉树的镜像
解法一:递归
public class Solution {
public void Mirror(TreeNode root) {
if(root == null ||(root.left == null && root.right == null)){
return;
}
TreeNode tem = root.left;
root.left = root.right;
root.right = tem;
if(root.left != null){
Mirror(root.left);
}
if(root.right != null){
Mirror(root.right);
}
}
}