题目描述:数字分类
给定一系列正整数,请按要求对数字进行分类,并输出以下5个数字:
A1 = 能被5整除的数字中所有偶数的和;
A2 = 将被5除后余1的数字按给出顺序进行交错求和,
即计算n1-n2+n3-n4…;
A3 = 被5除后余2的数字的个数;
A4 = 被5除后余3的数字的平均数,精确到小数点后1位;
A5 = 被5除后余4的数字中最大数字。
代码实现:
import java.util.*;
public class Main{
public static void main(String []args){
Scanner in=new Scanner(System.in);
int N=in.nextInt();
int num[]=new int[N];
int A1=0,A2=0,A3=0,A4=0,A5=0,flag=1,count=0;
for(int i=0;i<N;i++){
num[i]=in.nextInt();
if(num[i]%5==0){
if(num[i]%2==0)
A1+=num[i];
}
if(num[i]%5==1){
A2+=flag*num[i];
flag=-flag;
}
if(num[i]%5==2){
A3++;
}
if(num[i]%5==3){
A4+=num[i];
count++;
}
if(num[i]%5==4){
if(num[i]>A5)
A5=num[i];
}
}
if(A1!=0){
System.out.print(A1+" ");
} else{
System.out.print('N'+" ");
}
if(A2!=0){
System.out.print(A2+" ");
} else{
System.out.print('N'+" ");
}
if(A3!=0){
System.out.print(A3+" ");
} else{
System.out.print('N'+" ");
}
if(A4!=0){
System.out.print(A4/count+"."+(int)((A4%count*100/count+5)/10)+" ");
} else{
System.out.print("N"+" ");
}
if(A5!=0){
System.out.print(A5);
} else{
System.out.print("N");
}
}
}