27、给出每个员工每年薪水涨幅超过5000的员工编号emp_no

1、题目描述

给出每个员工每年薪水涨幅超过5000的员工编号emp_no、薪水变更开始日期from_date以及薪水涨幅值salary_growth,并按照salary_growth逆序排列。

提示:在sqlite中获取datetime时间对应的年份函数为strftime('%Y', to_date)


CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));

输入描述:

输出描述:

emp_no from_date salary_growth
10003 1995-12-03 24178
10008 1998-03-11 20843
10008 2000-03-10 5997

2、代码

select s1.emp_no,s2.from_date,(s2.salary-s1.salary) as salary_growth
from salaries s1 inner join salaries s2
on s1.emp_no=s2.emp_no
and salary_growth>5000
and (strftime("%Y",s2.to_date) - strftime("%Y",s1.to_date) = 1 
     OR strftime("%Y",s2.from_date) - strftime("%Y",s1.from_date) = 1 )
order by salary_growth desc;

自连接查询,按照题意进行筛选。

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转载自www.cnblogs.com/guoyu1/p/12711021.html