线程通信小练习

需求:编写两个线程,一个 线程打印1-52,另一个线程打印字母A-Z答应顺序是12A34B…,即按照整数和字母的顺序从小到大打印,并且每打印两个整数后,打印一个字母,交替循环打印
打印类:printer .java

public class Printer {
	// 打印次数
	private int index = 1;

	// 打印数字的方法
	public synchronized void Print(int i) {
			while(index%3==0){
				try {
					this.wait();
				} catch (InterruptedException e) {
					e.printStackTrace();
				}
			}
			try {
				Thread.sleep(100);
			} catch (InterruptedException e) {
				e.printStackTrace();
			}
		System.out.print(i);
		index++;
		this.notifyAll();
	}

	// 打印字母的方法
	public synchronized void Print(char c) {
		while(index%3!=0){
			try {
				this.wait();
			} catch (InterruptedException e) {
				e.printStackTrace();
			}
		}
		try {
			Thread.sleep(100);
		} catch (InterruptedException e) {
			e.printStackTrace();
		}
	System.out.print(c);
	index++;
	this.notifyAll();
	}
}

打印数字线程

public class PrintNum implements Runnable {
	private Printer printer;
	
	/**
	 * @param printer
	 */
	public PrintNum(Printer printer) {
		super();
		this.printer = printer;
	}

	@Override
	public void run() {
		for (int i = 1; i <= 52; i++) {
			printer.Print(i);
		}
	}

}

打印字母的线程

public class LetterPrint implements Runnable {

	private Printer printer;
	
	/**
	 * @param printer
	 */
	public LetterPrint(Printer printer) {
		super();
		this.printer = printer;
	}
	@Override
	public void run() {
		for (char c='A';c<='Z';c++) {
			printer.Print(c);
		}
	}
}

测试程序

public class Test {
	public static void main(String[] args) {
		Printer printer = new Printer();
		new Thread(new PrintNum(printer)).start();
		
		new Thread(new LetterPrint(printer)).start();
	}

}
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转载自blog.csdn.net/weixin_44804206/article/details/105603563
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