1、将一个字符串进行反转,将一个字符串中指定的部分进行反转,比如“abcdefg”反转为“abfedcg"
方式1:转为char[]
public String reverse(String str, int startIndex, int endIndex) {
if (str != null) {
char[] arr = str.toCharArray();
for (int x = startIndex, y = endIndex; x < y; x++, y--) {
char temp = arr[x];
arr[x] = arr[y];
arr[y] = temp;
}
return new String(arr);
}
return null;
}
方式二:使用string拼接
public String reverse1(String str, int startIndex, int endIndex) {
if (str != null) {
//1
String reverseStr = str.substring(0, startIndex);
//2
for (int i = endIndex; i < startIndex; i++) {
reverseStr += str.charAt(i);
}
//3
reverseStr += str.substring(endIndex - 1);
return reverseStr;
}
return null;
}
方式三:使用StringBuffer 和 StringBuilder替换string
public String reverse2(String str, int startIndex, int endIndex) {
if (str != null){
//1
StringBuilder builder = new StringBuilder(str.length());
builder.append(str.substring(0,startIndex));
//2
for (int i = endIndex ;i>=startIndex;i++){
builder.append(str.charAt(i));
}
//3
builder.append(str.substring(endIndex +1));
return builder.toString();
}
return null;
}
调用任意一种方法
String str = "abcdefg";
String reverse = reverse(str, 2, 5);
System.out.println(reverse);
2、 获取一个字符串在另一个字符串中出现的次数 比如 :”ab“在"absfabasdgabdadgsabaweavabagsdb"出现的次数
public int getCount(String mainStr, String subStr) {
int mainLength = mainStr.length();
int subLength = subStr.length();
int count = 0;
int index = 0;
if (mainLength >= subLength) {
//1
// while ((index = mainStr.indexOf(subStr)) != -1) {
// count++;
// mainStr = mainStr.substring(index + subStr.length());
// }
while ((index = mainStr.indexOf(subStr,index)) != -1) {
count++;
index += subLength;
}
return count;
} else {
return 0;
}
}
@Test//单元测试方法
public void testGetCount(){
String mainStr = "absfabasdgabdadgsabaweavabagsdb";
String subStr = "ab";
int count =getCount(mainStr,subStr);
System.out.println(count);
}
3、 获取两个字符串的最大相同子串
public String getMaxSameString(String str1, String str2) {
if (str1 != null && str2 != null) {
String maxStr = (str1.length() >= str2.length()) ? str1 : str2;
String minStr = (str1.length() <= str2.length()) ? str1 : str2;
int length = minStr.length();
for (int i = 0; i < length; i++) {
for (int x = 0, y = length - i; y <= length; x++, y++) {
String subStr = minStr.substring(x, y);
if (maxStr.contains(subStr)) {
return subStr;
}
}
}
}
return null;
}
@Test
public void test(){
String str1 = "badsvashellowanndsan";
String str2 = "afwahelloanig ";
String maxSameString = getMaxSameString(str1,str2);
System.out.println(maxSameString);
}