#!/bin/bash
for i in `seq 1 9`
do
for j in `seq 1 9`
do
[ $j -le $i ] && echo -n "$j*$i=`echo $(($i*$j))` "
done
echo " "
done
效果图如下
#!/bin/bash
for i in `seq 1 9`
do
for j in `seq 1 9`
do
[ $j -le $i ] && echo -n "$j*$i=`echo $(($i*$j))` "
done
echo " "
done
效果图如下