class Solution {
public:
int GetUglyNumber_Solution(int index) {
if(index < 0)
{
return -1;
}
long int dp[index + 1];
dp[0] = 0;
dp[1] = 1;
long int *n2, *n3, *n5;
n2 = n3 = n5 = &dp[1];
for(int i = 2; i <= index; i++) {
dp[i] = min(*n2 * 2, min(*n3 * 3, *n5 * 5));
if(*n2 * 2 == dp[i]) n2++;
if(*n3 * 3 == dp[i]) n3++;
if(*n5 * 5 == dp[i]) n5++;
}
return dp[index];
}
};
剑指Offer_编程题 | 丑数
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