A. Powered Addition time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You have an array aa of length nn. For every positive integer xx you are going to perform the following operation during the xx-th second:
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You have to make aa nondecreasing as fast as possible. Find the smallest number TT such that you can make the array nondecreasing after at most TT seconds. Array aa is nondecreasing if and only if a1≤a2≤…≤ana1≤a2≤…≤an. You have to answer tt independent test cases. Input The first line contains a single integer tt (1≤t≤1041≤t≤104) — the number of test cases. The first line of each test case contains single integer nn (1≤n≤1051≤n≤105) — the length of array aa. It is guaranteed that the sum of values of nn over all test cases in the input does not exceed 105105. The second line of each test case contains nn integers a1,a2,…,ana1,a2,…,an (−109≤ai≤109−109≤ai≤109). Output For each test case, print the minimum number of seconds in which you can make aa nondecreasing. Example input Copy 3 4 1 7 6 5 5 1 2 3 4 5 2 0 -4 output Copy 2 0 3 Note In the first test case, if you select indices 3,43,4 at the 11-st second and 44 at the 22-nd second, then aa will become [1,7,7,8][1,7,7,8]. There are some other possible ways to make aa nondecreasing in 22 seconds, but you can't do it faster. In the second test case, aa is already nondecreasing, so answer is 00. In the third test case, if you do nothing at first 22 seconds and select index 22 at the 33-rd second, aa will become [0,0][0,0]. |
#include <bits/stdc++.h>
using namespace std;
const int maxn=100001;
typedef long long ll;
int main()
{
int t;
scanf("%d",&t);
while(t--)
{
int n;
scanf("%d",&n);
int a[maxn];
for(int i=1; i<=n; i++)
scanf("%d",&a[i]);
int x=a[1];
int k=0;
for(int i=2; i<=n; i++)
{
x=max(x,a[i]);
if(a[i]<x)
k=max(k,x-a[i]);
}
if(k==0)
{
printf("0\n");
continue;
}
int i=0;
ll p=0;
ll ans=0;
for(i=1;; i++)
{
if(i==1)
p=1;
else
p=p*2;
ans+=p;
if(ans>=k)
break;
}
printf("%lld\n",i);
}
return 0;
}