来源:https://blog.csdn.net/u011815404/article/details/79252661
#include <iostream>
#include <cmath>
using namespace std;
int main()
{
int m,money;
char ch;
cin>>m>>ch;
if(m>1000) money=8+ceil((m-1000)/500.0)*4;
else money=8;
if(ch=='y') money=money+5;
cout<<money<<endl;
return 0;
}
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原文链接:https://blog.csdn.net/u011815404/article/details/79252661
要点:1.ceil用法
该函数返回不小于 x 的最小整数值。
*2.money=8+ceil((m-1000)/500.0)4;如果/500而不是/500.0会出错
#include <stdio.h>
#include <math.h>
int main ()
{
float val1, val2, val3, val4;
val1 = 1.6;
val2 = 1.2;
val3 = 2.8;
val4 = 2.3;
printf ("value1 = %.1lf\n", ceil(val1));
printf ("value2 = %.1lf\n", ceil(val2));
printf ("value3 = %.1lf\n", ceil(val3));
printf ("value4 = %.1lf\n", ceil(val4));
return(0);
}
运行结果:
value1 = 2.0
value2 = 2.0
value3 = 3.0
value4 = 3.0