AC代码:
//PAT_A 1031
#include<cstdio>
#include<cstring>
int main() {
char str[100];
scanf("%s", str);
int N = strlen(str);
int n1 = (N + 2) / 3, n3 = n1, n2 = N + 2 - n1 - n3;
for (int i = 0; i < n1 - 1; i++) {
printf("%c", str[i]);
for (int j = 0; j < n2 - 2; j++)printf(" ");
printf("%c\n", str[N - 1 - i]);
}
for (int i = 0; i < n2; i++) {
printf("%c",str[n1 + i - 1]);
}
return 0;
}