orderTuple = (
(77, '蚂蚁矿机T9 12T','1'),
(77, '蚂蚁阿瓦隆5代矿机','2'),
(77, '蚂蚁黑白矿机ST10','3'),
(78, '蚂蚁矿机L3+ 504M','4'),
(78, '蚂蚁黑白矿机ST10','5'),
(79, '阿瓦隆5代矿机','6'),
(79, '蚂蚁黑白矿机ST10','7'),
(79, '蚂蚁阿瓦隆5代矿机','8')
)
变为
orderDict = {
77: (('蚂蚁矿机T9 12T', '1'), ('蚂蚁阿瓦隆5代矿机', '2'), ('蚂蚁黑白矿机ST10', '3')),
78: (('蚂蚁矿机L3+ 504M', '4'), ('蚂蚁黑白矿机ST10', '5')),
79: (('阿瓦隆5代矿机', '6'), ('蚂蚁黑白矿机ST10', '7'), ('蚂蚁阿瓦隆5代矿机', '8'))
}
orderRes = {}
for n in orderTuple:
t = ((n[1],n[2]),)
if n[0] not in orderRes:
orderRes[n[0]] = t
else:
orderRes[n[0]] += t
python3 元组取出相同值作为字典的键
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转载自blog.csdn.net/qq_21389693/article/details/105734854
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