Java数组与vector互转,再排序

/*
Object[] object1 = null ; //数组定义
Vector<Object> object2;//Vector定义
object2 = new Vector<Object>(Arrays.asList(object1));// array -> vector
object1 = object2 .toArray( new Object[object2 .size()]);// vector ->array
*/
Integer[] object1={0,10,20,30,40,50,60,70,80,90,100};//数组定义
Vector<Integer> object2;//Vector定义
object2=new Vector<Integer>(Arrays.asList(object1));//[] -> array -> vector
System.err.println(Arrays.toString(object1));
System.err.println(object2);    
Integer[] object3 = object2.toArray(new Integer[object2.size()]);//vector -> array -> []
System.out.println(Arrays.toString(object3));

首先是将Vector转换为数组,然后再用冒泡排序,去找到最小的值,然后交换。代码如下:

  1. public static Elem[] getSort(Elem[] keys) {  
  2.   
  3.         for (int i = 0; i < keys.length - 1; i++) {  
  4.             for (int j = 0; j < keys.length - i - 1; j++) {  
  5.                 Elem pre = keys[j];  
  6.                 Elem next = keys[j + 1];  
  7.                 if (pre.get() > next.get()) {  
  8.                     Elem temp = pre;  
  9.                     keys[j] = next;  
  10.                     keys[j + 1] = temp;  
  11.                 }  
  12.             }  
  13.         }  
  14.         return keys;  
  15.     }  

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转载自blog.csdn.net/boguesfei/article/details/80444822