PAT练习题 1001 A+B Format
Calculate a+b and output the sum in standard format – that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input Specification:
Each input file contains one test case. Each case contains a pair of integers a and b where −106≤a,b≤106. The numbers are separated by a space.
Output Specification:
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input:
-1000000 9
Sample Output:
-999,991
题意
实现a+b,将结果进行标准化输出——从最后三位开始,每三位用“,”进行分隔。a和b的范围题目中已经给了。
输入格式:a空格b
输出格式:标准化结果
解题关键
- 这道题比较简单,利用C进行编程会提高解题速度
- 输入a和b,进行加法运算
- 关键的操作就是对结果的转化
代码思路和分析
- 将sum的每位数字使用while循环存入数组(此处使用abs绝对值函数)
- 根据数组的长度进行循环,每隔三位输出","即可
实现代码
#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,a,b,sum,num1,num2;
int num[8];
i = 0;
scanf("%d%d",&a,&b);
sum = a+b;
if(sum<0)
printf("-");
if(sum==0)
{
printf("0");
exit(0);
}
while(sum)
{
num[i] = abs(sum%10);
i++;
sum/=10;
}
for(j = i-1;j>=0;j--)
{
printf("%d",num[j]);
if(j%3==0&&j!=0)
printf(",");
}
return 0;
}
总结
这种方法也算是暴力解法,但在时间上的处理会更快一些,同时在测试的时候也可以减少这道题浪费的时间。