leetcode之栈的压入、弹出序列

输入两个整数序列,第一个序列表示栈的压入顺序,请判断第二个序列是否为该栈的弹出顺序。假设压入栈的所有数字均不相等。例
如,序列 {1,2,3,4,5} 是某栈的压栈序列,序列 {4,5,3,2,1} 是该压栈序列对应的一个弹出序列,但 {4,3,5,1,2} 就不可能是该压栈序列的弹出序列。
输入:pushed = [1,2,3,4,5], popped = [4,5,3,2,1]
输出:true
解释:我们可以按以下顺序执行:
push(1), push(2), push(3), push(4), pop() -> 4,
push(5), pop() -> 5, pop() -> 3, pop() -> 2, pop() -> 1

来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/zhan-de-ya-ru-dan-chu-xu-lie-lcof

思路

/*********利用栈操作*********/
class Solution {
    public boolean validateStackSequences(int[] pushed, int[] popped) {
        Deque<Integer> stack = new LinkedList();
        int p = 0;
        for(int i=0;i<pushed.length;i++){
            stack.push(pushed[i]);
            while(!stack.isEmpty() && stack.peek() == popped[p]){
                stack.pop();
                p++;
            }
        }
        return stack.isEmpty();
    }
}
/*********利用双指针模拟栈操作*********/
class Solution {
    public boolean validateStackSequences(int[] pushed, int[] popped) {
       int stack = -1;
       int p = 0;
       for(int i=0;i<pushed.length;i++){
           pushed[++stack] = pushed[i];
           while(stack >= 0 && stack <= pushed.length && pushed[stack] == popped[p]){
               stack--;
               p++;
           }
       }
       return stack == -1;
    }
}

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转载自blog.csdn.net/harryshumxu/article/details/105341502