def createCounter(): n = 0 def counter(): nonlocal n n+=1 return n return counter # 测试: counterA = createCounter() print(counterA(), counterA(), counterA(), counterA(), counterA()) # 1 2 3 4 5 counterB = createCounter() if [counterB(), counterB(), counterB(), counterB()] == [1, 2, 3, 4]: print('测试通过!') else: print('测试失败!')
利用闭包返回一个计数器函数,每次调用它返回递增整数
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