题目链接：Group Anagrams

• 题目描述：
  

Given an array of strings, group anagrams together.

For example, given: [“eat”, “tea”, “tan”, “ate”, “nat”, “bat”],

Return:

[
  ["ate", "eat","tea"],
  ["nat","tan"],
  ["bat"]
]

Note: All inputs will be in lower-case.

(1)思路：建立map<排序后字符串，vector<同一组anagram>>排序，对每个字符串都进行排序，排序之后结果相同的属于一组anagram。

(2)代码：

class Solution {
public:
    vector<vector<string>> groupAnagrams(vector<string>& strs) {
        map<string, vector<string>> sorted;
        for (int i = 0; i < strs.size(); i++) {
            string temp = strs[i];
            sort(temp.begin(), temp.end());
            if (sorted.count(temp) == 1)    sorted[temp].push_back(strs[i]);
            else {
                vector<string> entry;
                entry.push_back(strs[i]);
                sorted.insert(pair<string, vector<string>>(temp, entry));
            }
        }
        vector<vector<string>> ans;
        for (map<string, vector<string>>::iterator i = sorted.begin(); i != sorted.end(); i++) {
            ans.push_back(i->second);
        }
        return ans;
    }
};

(3)提交结果：