类型转换问题代码
//数据重组
uint32_t u32Address = 0;
uint8_t u8Buffer[4] = {0x12, 0x34, 0x56, 0x78};
for (int i = 0; i < 4; i++) {
u32Address += (uint32_t)(u8Buffer[i] << ((3 - i) * 8));
}
问题分析及修正后代码
u8Buffer数组为uint8类型，在左移位过程数据丢失，在最外层加强制类型转化已晚，正确办法是在移位前转换类型，代码如下：
//数据重组
uint32_t u32Address = 0;
uint8_t u8Buffer[4] = {0x12, 0x34, 0x56, 0x78};
for (int i = 0; i < 4; i++) {
u32Address += ((uint32_t)u8Buffer[i] << ((3 - i) * 8));
}