题解
原题链接
开一个数组保存N在当前进制b下的每一项,判断左右是否相等
#include <cstdio>
using namespace std;
int main()
{
int N, b, a[40], len=0;
bool ispa = true;
scanf("%d %d",&N,&b);
while(N != 0)
{
a[len++] = N%b;
N /= b;
}
for (int i=0; i<len/2; i++)
{
if (a[i] != a[len-1-i])
{
ispa = false;
printf("No\n");
break;
}
}
if (ispa == true)
printf("Yes\n");
for (int i=len-1; i>0; i--)
printf("%d ", a[i]);
printf("%d", a[0]);
return 0;
}