#include<stdio.h>
#include<math.h>
int main()
{
float fun(float a, float b, float(*p)(float, float));
float fun1(float,float);
float fun2(float, float);
float fun3(float, float);
float fun4(float, float);
float fun5(float, float);
int n;
printf("please input a number of function from 1 to 5:\n");
scanf_s("%d", &n);
switch (n)
{
case 1:printf("this is the first function,");
fun(1, 4,fun1);
break;
case 2:printf("this is the second function,");
fun(1, 4,fun2);
break;
case 3:printf("this is the third function,");
fun(1, 4,fun3);
break;
case 4:printf("this is the 4th function,");
fun(1, 4,fun4);
break;
case 5:printf("this is the 5th function,");
fun(1, 4,fun5);
break;
default:printf("DATA ERROR");
}
return 0;
}
float fun(float x, float y, float(*p)(float, float))
{
float result;
result = (*p)(x, y);
printf("the integrate of the function is %8.2f\n", result);
}
float fun1(float a, float b)
{
float sum;
sum = b + 0.5*b*b - a - 0.5*a*a;
return sum;
}
float fun2(float a, float b)
{
float sum;
sum = b * b + 3 * b - a * a - 3 * a;
return sum;
}
float fun3(float a, float b)
{
float sum;
sum = exp(b) + b - exp(a) - a;
return sum;
}
float fun4(float a, float b)
{
float sum;
sum = (1.0 / 3.0)*(pow((1 + b), 3)) - (1.0 / 3.0)*(pow((1 + a), 3));
return sum;
}
float fun5(float a, float b)
{
float sum;
sum = (1.0 / 4.0)*pow(b, 4) - (1.0 / 4.0)*pow(a, 4);
return sum;
}
利用指针变量调用他所指向的函数求定积分,列举了5个普通的函数,代码如下
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转载自blog.csdn.net/progess_every_day/article/details/104860316
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