JZ16 合并两个排序的链表

题目描述

输入两个单调递增的链表,输出两个链表合成后的链表,当然我们需要合成后的链表满足单调不减规则。

/*
public class ListNode {
    int val;
    ListNode next = null;

    ListNode(int val) {
        this.val = val;
    }
}*/
public class Solution {
    
    
    public ListNode Merge(ListNode list1,ListNode list2) {
    
    
       ListNode  head = new ListNode(0);
       ListNode mergelist = head;
       while (list1 != null && list2 != null){
    
    
           if (list1.val > list2.val) {
    
    
               mergelist.next = list2;
               list2 = list2.next;
           }else {
    
    
               mergelist.next = list1;
               list1 = list1.next;
           }
           mergelist = mergelist.next;
       }

        if (list1 == null) mergelist.next = list2;
        if (list2 == null) mergelist.next = list1;
            
        return head.next;

    }

}

在这里插入图片描述

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转载自blog.csdn.net/qq_41620020/article/details/108603626