typescript add函数,要求参数类型相同,否则报错

const add = (...res: Array<string>|Array<number>) => {
    return res.reduce((total, num) => total + num, 0);
}

add(1, 2, 3);
add('a', 'b', 'c');
add('a', 1, 2);

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转载自blog.csdn.net/u013475983/article/details/89294069