class Solution:
def commonChars(self, A: List[str]) -> List[str]:
res = []
min_lenth_char = min(A,key = len)
for char in min_length_char:
if all(char in item for item in A):
res.append(char)
A = [i.replace(char,'',1) for i in A]
return res
Leetcode 1002查找常用字符 -python之美
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转载自blog.csdn.net/weixin_43812609/article/details/109105923
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