一、闰年判断条件

• 能被4整除，并且不能被100整除
• 能被400整除

二、输出指定范围的闰年

1、创建程序 - 输出指定范围的闰年及个数.py

# -*- coding: utf-8 -*-
"""
Created on Thu Oct 15 11:10:35 2020

@author: howard

输出指定范围的闰年及个数
"""
import calendar

def getLeapYears01(start, end):
    leap_years = []
    for year in range(start, end + 1):
        if year % 4 == 0 and year % 100 != 0 or year % 400 == 0:
            leap_years.append(year)
    return leap_years, len(leap_years)

def getLeapYears02(start, end):
    leap_years = [year for year in range(start, end + 1) if calendar.isleap(year)]
    return leap_years, len(leap_years)   

if __name__ == '__main__':
    print('方法一：')
    leap_years, count = getLeapYears01(1972, 2020)
    print('{}与{}之间有{}个闰年。'.format(1972, 2020, count))
    print(leap_years)    
    
    print('方法二：')
    leap_years, count = getLeapYears02(1972, 2020)
    print('{}与{}之间有{}个闰年。'.format(1972, 2020, count))
    print(leap_years)
    
    print('方法三：')
    print('{}与{}之间有{}个闰年。'.format(1972, 2020, calendar.leapdays(1972, 2021)))   

2、运行程序，查看结果