/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
Map<String,Integer> count;
List<TreeNode> ans;
public List<TreeNode> findDuplicateSubtrees(TreeNode root) {
count = new HahMap();
ans = new ArrayList();
collect(root);
return ans;
}
public String collect(TreeNode node){
if(node == null) return "#";
String serial = node.val + "," + collect(node.left)+","+collect(node.right);
count.put(serial,count.getOrDefault(serial,0)+1);
if(count.get(serial) == 2){
ans.add(node);
}
return serial;
}
}
每日一道Leetcode - 652. 寻找重复的子树【树】
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转载自blog.csdn.net/weixin_41041275/article/details/112251015
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