1、计算从1到100所有整数的和
for
sum=0
for i in {
1..100}
do
sum=$[$i+$sum]
done
echo $sum
while
#!/bin/bash
sum=0
i=1
while [ $i -le 100 ]
do
sum=$[$sum+$i]
let i++
done
echo "$sum"
2、提示用户输入一个小于100的整数,并计算从1到该数之间所有整数的和
for
#!/bin/bash
read -p "输入小于100的一个整数:" a
sum=0
for ((i=1;i<=a;i++))
do
sum=$[$sum+$i]
done
echo "1到输入值之间的整数和为$sum"
while
#!/bin/bash
read -p "输入一个小于100的整数:" a
sum=0
while [ $a -ge 1 ]
do
sum=$[$sum+$a]
let a--
done
echo "1到输入值之间的整数和为$sum"
3、求从1到100所有整数的偶数和、奇数和
for
#!/bin/bash
a=0
b=0
for i in {
0..100..2}
do
a=$[$a+$i]
done
echo "奇数和为$a"
for i in {
1..100..2}
do
b=$[$b+$i]
done
echo "偶数和为$b"
while
#!/bin/bash
a=0
b=0
i=1
c=0
while [ $i -le 100 ]
do
a=$[$a+$i]
let i=$[$i+2]
done
echo "奇数和为$a"
while [ $c -le 100 ]
do
b=$[$b+$c]
let c=$[$c+2]
done
echo "偶数和为$b"
4、写个逛淘宝选购商品脚本,每家商店有五种商品选购(衣服500元,裤子400元,鞋子350元,帽子150元,袜子50元),每次选购完或不买都会提示用户是否继续逛下一家商店,如果不再继续逛的话进行购物车结算总额。
#!/bin/bash
i=1
sum=0
while true
do
echo "来到第$i家商店门口"
read -p "是否进入看看(yes/no)" doing
while [ $doing = "yes" ]
do
echo "1:衣服¥500"
echo "2:裤子¥400"
echo "3:鞋子¥350"
echo "4:帽子¥150"
echo "5:袜子¥50"
echo "其他:放弃购买"
read -p "请选择需要购买的商品序列:" num
case $num in
1)
echo "衣服购买成功"
sum=$[sum+=500]
;;
2)
echo "裤子购买成功"
sum=$[sum+=400]
;;
3)
echo "鞋子购买成功"
sum=$[sum+=350]
;;
4)
echo "帽子购买成功"
sum=$[sum+=150]
;;
5)
echo "袜子购买成功"
sum=$[sum+=50]
;;
*)
echo "放弃购买"
esac
read -p "是否继续在这家店购物(yes/no)" doing
done
read -p "是否继续逛街(yes/no)" going
if [ $going = "yes" ]
then
let i++
else
break
fi
done
echo -e "一共经过$i家店。\n合计购物总价:$sum。"