1005 Spell It Right (20 分)

思路

非常大串的数字，利用string类型完美解决～

代码

#include<bits/stdc++.h>
using namespace std;

int main()
{
    
    
    string str;
    cin>>str;
    int len = str.length();
    int a[10] ={
    
    0};

    string strs[10]={
    
    "zero","one","two","three","four","five","six","seven","eight","nine"} ;
    for(int i =0;i<len;i++)
    {
    
    
        if(int(str[i])==48)
            a[0]+=1;
        else if(int(str[i])==49)
            a[1]+=1;
        else if(int(str[i])==50)
            a[2]+=1;
        else if(int(str[i])==51)
            a[3]+=1;
        else if(int(str[i])==52)
            a[4]+=1;
        else if(int(str[i])==53)
            a[5]+=1;
        else if(int(str[i])==54)
            a[6]+=1;
        else if(int(str[i])==55)
            a[7]+=1;
        else if(int(str[i])==56)
            a[8]+=1;
        else if(int(str[i])==57)
            a[9]+=1;
    }

    int sum = 0;
    for (int i =0;i<10;i++)
        sum += i * a[i];

    
    if (sum>=100)
        cout<<strs[sum/100]<<' '<<strs[sum/10%10]<<' '<<strs[sum%10];
    else if (sum >= 10)
        cout<<strs[sum/10]<<' '<<strs[sum%10];
    else
        cout<<strs[sum];
    
    
}