Calculate a+b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input Specification:
Each input file contains one test case. Each case contains a pair of integers a and b where −106≤a,b≤106. The numbers are separated by a space.
Output Specification:
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input:
-1000000 9
Sample Output:
-999,991
Example:
#include <iostream>
#include <stack>
using namespace std;
int main()
{
int a, b;
cin >> a >> b;
int c = a + b;
if(c == 0) {
cout << 0;
} else {
cout << (c > 0 ? "" : "-");
c = (c > 0 ? c : -c);
stack<char> s;
int i = 0;
while(c) {
s.push(c % 10 + '0');
c /= 10;
++i;
if(c && i % 3 == 0) s.push(',');
}
while(!s.empty()) {
cout << s.top();
s.pop();
}
}
return 0;
}
思路:
利用入栈,出栈操作将结果输出。