求a+aa+aaa+aaaa+...+aaaaaaaaa(n个a)的值,n是一个数

求a+aa+aaa+aaaa+…+aaaaaaaaa(n个a)的值,n是一个数值

#include <stdio.h>
#include <stdlib.h>
int main()
{
    
    
	int a = 0;
	int n = 0;
	scanf("%d%d", &a, &n);
	int sum = 0;
	int i = 0;
	int ret = 0;
	for (i = 0; i < n; i++)
	{
    
    
		ret = ret * 10 + a;
		sum += ret;
	}
	printf("%d\n", sum);
	system("pause");
	return 0;
}

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转载自blog.csdn.net/weixin_54748281/article/details/114011965