按照题意进行模拟即可,注意%的转义符为‘%’
#include <cstdio>
int n, D;
double e;
int main(){
scanf("%d %lf %d", &n, &e, &D);
int knk=0, k=0;
for(int i=0; i<n; i++){
int day;
int sum = 0;
scanf("%d", &day);
for(int j=0; j<day; j++){
double dian;
scanf("%lf", &dian);
if(dian < e) sum++;
}
if(sum>(day/2) && day>D){
k++;
}else if(sum>(day/2)){
knk++;
}
}
printf("%.1f%% ", knk/(n*1.0)*100);
printf("%.1f%%", k/(n*1.0)*100);
return 0;
}