#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
#define INF 0x3f3f3f3f
int main(){
int flag=0,ans=0,x,sum=0;;
for(int i=0;i<12;i++){
cin>>x;
sum+=300;
sum-=x;
if(sum<0){
cout<<"-"<<i+1;
flag=1;
break;
}
else if(sum>=100){
ans=ans+(sum/100)*100;
sum-=(sum/100)*100;
}
}if(!flag)cout<<ans*1.2+sum;//加sum
return 0;
}
luogu part1.1 津津的储蓄计划 (基础题)
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转载自blog.csdn.net/Minelois/article/details/113666970
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