配置Tomcat 8.5
步骤回头再写。。。。。。
web.xml
因为我用是注解, 所以里面啥都没写
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<!-- 目前是空的 -->
</web-app>
Servlet
package com.servlet;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;
/**
* WebServlet注解描述Servlet
* Servlet的名字(选填)
* urlPatterns(也可以是value)表示访问的URL(必填), 可以写多个
* LoginServlet前面的'/'不能少
*/
@WebServlet(name = "LoginServlet", urlPatterns = "/LoginServlet")
public class LoginServlet extends HttpServlet {
@Override
protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
doPost(req, resp);
}
@Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
//防止中文乱码
req.setCharacterEncoding("utf-8");
String name = req.getParameter("name");
String password = req.getParameter("password");
System.out.println(name);
System.out.println(password);
}
}
login.html
<!DOCTYPE html>
<html lang="zh">
<head>
<meta charset="UTF-8">
<title>登陆</title>
</head>
<body>
<!-- action填写LoginServlet -->
<form action="LoginServlet" method="post">
账号: <input type="text" name="name" /><br>
密码: <input type="password" name="password" /><br>
<input type="submit" value="登陆" />
</form>
</body>
</html>
运行
打开Tomcat
打开login.html
输入账号密码,
看控制台
End!
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