原理
图像混合实际上是像素之间的运算
于是要求
要求两张图象大小一致
API
add(src1, src2, dst=None, mask=None, dtype=None) // +
multiply(src1, src2, dst=None, scale=None, dtype=None) // -
subtract(src1, src2, dst=None, mask=None, dtype=None) // x
divide(src1, src2, dst=None, scale=None, dtype=None) // /
代码
#include <opencv2/opencv.hpp>
#include <iostream>
using namespace std;
using namespace cv;
int main(int argc, char** argv) {
Mat src1, src2, dst;
src1 = imread("C:/Users/86176/Pictures/pics/baboon.tiff");
src2 = imread("C:/Users/86176/Pictures/pics/peppers(1).tiff");
if (!src1.data) {
cout << "could not load image which named boy.png..." << endl;
return -1;
}
if (!src2.data) {
cout << "could not load image named girl.png..." << endl;
return -1;
}
double alpha = 0.5;
if (src1.rows == src2.rows && src1.cols == src2.cols && src1.type() == src2.type()) {
add(src1, src2, dst, Mat());
//multiply(src1, src2, dst, Mat());
//subtract(src1, src2, dst, 1.0);
//divide(src1, src2, dst, 1.0);
imshow("src1", src1);
imshow("src2", src2);
imshow("dst", dst);
}
else {
printf("could not blend images , the size of images is not same...\n");
return -1;
}
waitKey(0);
return 0;
}
效果
src1
src2