今天在刷Leetcode题时,明明语法没有错误(如下),但是一直出错,郁闷
select Score,
dense_rank() over(order by Score desc) as Rank
from Scores;
想了很久,原来是关键字作为列名时需要加上引号
select Score,
dense_rank() over(order by Score desc) as 'Rank'
from Scores;
加上引号就对了
今天在刷Leetcode题时,明明语法没有错误(如下),但是一直出错,郁闷
select Score,
dense_rank() over(order by Score desc) as Rank
from Scores;
想了很久,原来是关键字作为列名时需要加上引号
select Score,
dense_rank() over(order by Score desc) as 'Rank'
from Scores;
加上引号就对了