E. Bus Video System

input

4 10
2 4 1 2

output

2

code

//Siberian Squirrel
#include<bits/stdc++.h>

#define IO ios::sync_with_stdio(false);cin.tie(0);cout.tie(0)
#define ACM_LOCAL

using namespace std;
typedef long long ll;

const int INF = 0x3f3f3f3f;
const int N = 2e5 + 10;
const int MOD = 998244353;

ll n, m, k, w;
int f[N], a[N];

ll quick_pow(ll ans, ll p, ll res = 1) {
    
    
    for(; p; p >>= 1, ans = ans * ans % MOD)
        if(p & 1) res = res * ans % MOD;
    return res % MOD;
}

ll inv(ll ans) {
    
    
    return quick_pow(ans, MOD - 2);
}

ll C(int n, int m) {
    
    
    if(n < m || n <= 0 || m < 0) return 0;
    if(m == 0) return 1;
    return 1ll * f[n] * inv(f[m]) % MOD * inv(f[n - m]) % MOD;
}

inline void solve(ll res = 0, ll ans = 0) {
    
    
    ll maxx = 0, minn = 0;
    for(int i = 1; i <= n; ++ i) {
    
    
        res = (res + a[i]);
        maxx = max(maxx, res);
        minn = min(minn, res);
    }
    if(maxx > w || -minn > w) cout << 0 << endl;
    else {
    
    
        if(w - maxx + minn + 1 >= 0) cout << w - maxx + minn + 1 << endl;
        else cout << 0 << endl;
    }
}

int main() {
    
    
    IO;
#ifdef ACM_LOCAL
    freopen("input.txt", "r", stdin);
	freopen("output.txt", "w", stdout);
#endif
	f[0] = f[1] = 1;
	for(int i = 2; i < N; ++ i) f[i] = 1ll * f[i - 1] * i % MOD;
    int o = 1;
//    cin >> o;
    while(o --) {
    
    
        cin >> n >> w;
        for(int i = 1; i <= n; ++ i) cin >> a[i];
        solve();
    }

    return 0;
}