用WebService很久了,但都是利用axis2去生成服务端掉别人的接口,重来没有自己写过,也不知道怎么去配置,今天利用点闲暇时间上网查了些资料,结合公司的项目自己做了个测试,我用的是CXF结合sping配置的服务端。需要用到的jar包具体我也不是很了解,网上说要用到一下这些,我没有去测试,拿过来了。
commons-logging-1.1.jar geronimo-activation_1.1_spec-1.0-M1.jar (or Sun's Activation jar) geronimo-annotation_1.0_spec-1.1.jar (JSR 250) geronimo-javamail_1.4_spec-1.0-M1.jar (or Sun's JavaMail jar) geronimo-servlet_2.5_spec-1.1-M1.jar (or Sun's Servlet jar) geronimo-ws-metadata_2.0_spec-1.1.1.jar (JSR 181) jaxb-api-2.1.jar jaxb-impl-2.1.6.jar jaxws-api-2.1.jar jetty-6.1.5.jar jetty-util-6.1.5.jar neethi-2.0.jar saaj-api-1.3.jar saaj-impl-1.3.jar stax-api-1.0.1.jar wsdl4j-1.6.1.jar wstx-asl-3.2.1.jar XmlSchema-1.2.jar xml-resolver-1.2.jar
The Spring jars (optional - for XML Configuration support):
aopalliance-1.0.jar spring-core-2.0.4.jar spring-beans-2.0.4.jar spring-context-2.0.4.jar spring-web-2.0.4.jar
And the CXF jar:
cxf-2.1.jar
首先建立一个web项目,引入spring能力。
1. 建立webservice接口
package com; import javax.jws.WebParam; import javax.jws.WebService; @WebService public interface TestI { String sayHello(@WebParam(name="word")String word); }
2. 建立接口的实现类
package com; import javax.jws.WebService; @WebService(endpointInterface = "com.Test") public class Test implements TestI{ public String sayHello(String word) { System.out.println("HELLO"+word); return "HELLO"+word; } }
3 .配置spring配置文件applicationContext.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans
xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:jaxws="http://cxf.apache.org/jaxws"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://cxf.apache.org/jaxws
http://cxf.apache.org/schemas/jaxws.xsd">
<import resource="classpath:META-INF/cxf/cxf.xml" />
<import resource="classpath:META-INF/cxf/cxf-servlet.xml" />
<import resource="classpath:META-INF/cxf/cxf-extension-soap.xml" />
<jaxws:endpoint id="testWS"
address="/test"
implementorClass="com.TestI">
<jaxws:implementor>
<bean id="personDepotManagerImpl" class="com.Test"/>
</jaxws:implementor>
</jaxws:endpoint>
</beans>
红色部分是需要加入的,下面的jaxws就是对webservice暴露的接口的定义。implementorClass是接口, jaxws:implementor中的bean是实现类
4 . 配置web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>WEB-INF/classes/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<servlet>
<servlet-name>CXFServlet</servlet-name>
<servlet-class>org.apache.cxf.transport.servlet.CXFServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>CXFServlet</servlet-name>
<url-pattern>/cxf/*</url-pattern>
</servlet-mapping>
</web-app>
红色部分是对webservice的配置,其中/cxf/*就是指webservice的访问路径了,比如我的项目叫CXF,我的访问路径就是http://127.0.0.1:8080/CXF/cxf这样就能看到所有的webservice。目测红色没出来啊,ITEYE不给力啊咋回事