从pascalvoc的xml文件生成yolo标记文件和name文件
使用方法,拷贝入python文件,在xml文件夹上层目录运行
import os
import xml.etree.ElementTree as ET
import sys
'''
1.制作name.txt ok
2.制作train.txt
3.制作test.txt
'''
def convert(size, box): # 将PascalVoc数据转化为yolo
dw = 1. / size[0]
dh = 1. / size[1]
x = (box[0] + box[1]) / 2.0
y = (box[2] + box[3]) / 2.0
w = box[1] - box[0]
h = box[3] - box[2]
x = x * dw
w = w * dw
y = y * dh
h = h * dh
return x, y, w, h
def convert_annotation(image_id):
# in_file = open(image_id.replace('\\', '/'), 'rb')
in_file = image_id.replace('\\', '/')
out_file = open(image_id.split('.')[0] + '.txt', 'w')
tree = ET.parse(in_file) # 解析xml树
root = tree.getroot()
size = root.find('size')
w = int(size.find('width').text)
h = int(size.find('height').text)
for obj in root.iter('object'):
difficult = obj.find('difficult').text
cls = obj.find('name').text
if cls not in classes or int(difficult) == 1:
classes.append(cls)
# continue
cls_id = classes.index(cls)
xmlbox = obj.find('bndbox')
b = (float(xmlbox.find('xmin').text), float(xmlbox.find('xmax').text), float(xmlbox.find('ymin').text),
float(xmlbox.find('ymax').text))
bb = convert((w, h), b)
out_file.write(str(cls_id) + " " + " ".join([str(a) for a in bb]) + '\n')
# in_file.close()
out_file.close()
if __name__ == "__main__":
classes = []
wd = os.getcwd() # 获取当前文件目录
dir_list = os.listdir(wd)
dir_xml = []
for item in dir_list:
if os.path.isdir(item):
# dir.append(item)
dir_path = os.path.join(wd, item)
dir_list_temp = os.listdir(dir_path)
for item2 in dir_list_temp:
if os.path.isfile(dir_path.replace('\\', '/') + '/' + item2):
try:
if item2.split('.')[1] == 'xml':
dir_xml.append(dir_path + '/' + item2) # 此处搜集完所有xml文件路径名称放在dir中
except IndexError:
pass
for item in dir_xml:
# *****hahaha, 这一小段是整来耍的
sys.stdout.write('\r' + '/')
sys.stdout.flush()
sys.stdout.write('\r' + '|')
sys.stdout.flush()
sys.stdout.write('\r' + '\\')
sys.stdout.flush()
# print('\r'+'你的输出详情', flush=True)
try:
convert_annotation(item)
except:
pass
with open('object.names', 'w') as f: # 制作name文件
for item in classes:
f.write(item)
f.write('\n')