C++ 传递指针到函数

#include<iostream>
using namespace std;

void addFive(int Number){
    
    
	Number = Number + 5;
} 

int main(){
    
    
	int nMyNumber = 18; 
	cout<<"My original number is "<<nMyNumber<<endl;
	addFive(nMyNumber);//此处传递的是nMyNumber的一个副本
//	因此+5的也是副本,main中的nMyNumber没变 
	cout<<"My new number is "<<nMyNumber ;
	return 0; 
//最后结果无法输出23
}
 
#include<iostream>
using namespace std;

void addFive(int *Number){
    
    //Number前加*号
//是为了告诉编译器,们是指针所指的变量+5,不是指针自己+5
	*Number = *Number + 5;
} 

int main(){
    
    
	int nMyNumber = 18; 

	cout<<"My original number is "<<nMyNumber<<endl;
	
	addFive(&nMyNumber);

	cout<<"My new number is "<<nMyNumber ;
	return 0; 
}

若想让函数返回指针:
int * MyFunction():
在这句中,MyFunction返回一个指向整型的指针

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转载自blog.csdn.net/fly_ship/article/details/108739684