PAT甲级-map映射、stl的使用-1100 Mars Numbers解题思路

1100 Mars Numbers (20 分)

在这里插入图片描述

思路

打表
数字映射字符串,用string数组可以
字符串映射数字,用map

代码

#include<bits/stdc++.h>
using namespace std;

string unitDigit[13]={
    
    "tret","jan", "feb", "mar", "apr", "may", "jun", "jly", "aug", "sep", "oct", "nov", "dec"};
string tenDigdit[13] = {
    
    "tret","tam", "hel", "maa", "huh", "tou", "kes", "hei", "elo", "syy", "lok", "mer", "jou"};
map<string,int>strTonum;
string numTostr[170];

int main(){
    
    
    for(int i=0;i<13;i++){
    
    
        numTostr[i] = unitDigit[i];
        strTonum[unitDigit[i]] = i;

        numTostr[i*13] = tenDigdit[i];
        strTonum[tenDigdit[i]] = i*13;

    }
    for(int i=1;i<13;i++){
    
    
        for(int j=1;j<13;j++){
    
    
            string str = tenDigdit[i] +' '+unitDigit[j];
            numTostr[i*13+j]  = str;
            strTonum[str] = i*13+j;
        }
    }

    int N;
    cin>>N;
    string s;
    getchar();
    for(int i =0;i<N;i++)
    {
    
    
        getline(cin,s);
        int num = 0;
        if(s[0]>='0'&&s[0]<='9')
        {
    
    
            for(int j =0;j<s.length();j++)
                num = num*10+(s[j]-'0');
            cout<<numTostr[num]<<endl;
        }
        else cout<<strTonum[s]<<endl;

    }
}

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转载自blog.csdn.net/weixin_43999137/article/details/114663410