BUUCTF - re - rsa
http://tool.chacuo.net/cryptrsakeyparse 将key文件拖进去解析
可以得到
e=65537
n=0xC0332C5C64AE47182F6C1C876D42336910545A58F7EEFEFC0BCAAF5AF341CCDD
十进制就是n=86934482296048119190666062003494800588905656017203025617216654058378322103517
如下网址得到p q
p=285960468890451637935629440372639283459
q=304008741604601924494328155975272418463
然后就是常规的RSA,脚本直接得
import gmpy2
import rsa
e = 65537
n = 86934482296048119190666062003494800588905656017203025617216654058378322103517
p = 285960468890451637935629440372639283459
q = 304008741604601924494328155975272418463
phi_n = (q-1)*(p-1)
d = gmpy2.invert(e, phi_n)
key = rsa.PrivateKey(n, e, int(d), p, q)
with open("C:\\Users\\86177\\Desktop\\flag.txt", "rb+") as f:
f = f.read()
print(rsa.decrypt(f, key))
#flag{decrypt_256}