例子:
我有一个people class,同时list里装的都是people对象,people有两个属性值,一个是name,一个是age,这时候我想遍历取出其中的age属性。
一般都是直接for循环,如下:
class people():
def __init__(self, name, age):
self.name = name
self.age = age
peolist = []
peolist.append(people('ray', 12))
peolist.append(people('pick', 13))
peolist.append(people('pick1', 15))
print(list(item.age for item in peolist))
在java中可以用lambda表达式进行获取,在python中也一样,当然这样写会比较冗余,不过示例代码如下:
class people():
def __init__(self, name, age):
self.name = name
self.age = age
peolist = []
peolist.append(people('ray', 12))
peolist.append(people('pick', 13))
peolist.append(people('pick1', 15))
print(list(map(lambda x: x.age, peolist)))
运行结果如下:
如果是要取不重复的值,那就把最外层的list换成set就可以了