#include<stdio.h>
int main()
{
int n;
scanf("%d",&n);
getchar();
while(n--)
{
char c;
int y;
scanf("%c %d",&c,&y);
getchar();
if(c>='A'&&c<='Z')
printf("%d\n",y+c-'A'+1);
else
printf("%d\n",y-(c-'a'+1));
}
return 0;
}
2055 An easy problem(杭电)
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转载自blog.csdn.net/qq_59414507/article/details/120815726
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